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Nurse.ICU

NCLEX · practice

Acid-Base & ABGs — Set 1

Ten NCLEX-style arterial blood gas and acid-base questions, from naming the disorder to picking the right first action.

Physiological adaptation · Reduction of risk potential

10 questions · practice mode

  1. 1

    A nurse reviews an arterial blood gas for a client admitted with an acute COPD exacerbation: pH 7.30, PaCO₂ 58 mmHg, HCO₃⁻ 25 mEq/L. How should the nurse interpret this result?

    Correct: A

    The pH is acidic (below 7.35) and the PaCO₂ is elevated (above 45 mmHg) in the same acidic direction, so the lungs are the cause: respiratory acidosis. The HCO₃⁻ is still within the normal 22–26 mEq/L range, which means the kidneys have not yet begun to compensate — making it uncompensated. Full compensation would show a clearly elevated bicarbonate pulling the pH back toward normal, which hasn't happened here.

    • A. Correct. Acidic pH + high CO₂ (same direction) = respiratory acidosis; a normal bicarbonate means no compensation yet.
    • B. Fully compensated would require a normal pH (7.35–7.45) with an elevated bicarbonate — the pH here is still 7.30.
    • C. Respiratory alkalosis would show an alkalotic pH (above 7.45) with a low CO₂ — the opposite of these values.
    • D. Metabolic acidosis would show a low bicarbonate (below 22); this bicarbonate is normal, and the CO₂ is the abnormal value.
  2. 2

    A client with diabetic ketoacidosis has these values: pH 7.22, PaCO₂ 28 mmHg, HCO₃⁻ 12 mEq/L. Which interpretation is correct?

    Correct: D

    The pH is acidic and the HCO₃⁻ is low (below 22) in the same acidic direction, so the primary problem is metabolic acidosis — expected in DKA from ketoacid accumulation. The PaCO₂ is low (below 35), which is the lungs blowing off CO₂ (Kussmaul respirations) to raise the pH: respiratory compensation. Because the pH is still abnormal, compensation is partial, not complete.

    • A. Metabolic alkalosis needs an alkalotic pH and high bicarbonate — the opposite of these values.
    • B. A mixed acidosis would require the CO₂ to be high (adding acid); here the low CO₂ is helping, not a second acidosis.
    • C. Respiratory acidosis would show a HIGH CO₂; here the CO₂ is low.
    • D. Correct. Low pH + low bicarbonate = metabolic acidosis; the low CO₂ is compensatory.
  3. 3

    A client is admitted with persistent vomiting for three days. Which acid-base disturbance should the nurse most anticipate?

    Correct: A

    Prolonged vomiting removes hydrochloric acid from the stomach. Losing acid (hydrogen ions) leaves the blood relatively more basic, and the kidneys retain bicarbonate as chloride and volume drop — producing a metabolic alkalosis. Expect a high pH and a high HCO₃⁻, often with hypokalemia and hypochloremia.

    • A. Correct. Loss of gastric acid raises pH → metabolic alkalosis.
    • B. Respiratory acidosis is driven by hypoventilation and CO₂ retention.
    • C. Respiratory alkalosis is driven by hyperventilation, not GI acid loss.
    • D. Metabolic acidosis comes from gaining acid or losing bicarbonate (e.g., diarrhea, DKA), not vomiting.
  4. 4

    Which arterial blood gas value is the primary determinant of the respiratory component of acid-base balance?

    Correct: C

    PaCO₂ reflects how much carbon dioxide the lungs are retaining or blowing off, so it is the respiratory component. HCO₃⁻ is controlled by the kidneys and is the metabolic component. pH is the overall net result, and PaO₂ reflects oxygenation, not acid-base status.

    • A. Bicarbonate is the metabolic (kidney) component.
    • B. pH is the overall verdict, not specifically respiratory.
    • C. Correct. CO₂ is regulated by ventilation — the respiratory side.
    • D. PaO₂ measures oxygenation and is interpreted separately from acid-base.
  5. 5

    A client has: pH 7.37, PaCO₂ 60 mmHg, HCO₃⁻ 34 mEq/L. How should the nurse interpret this gas?

    Correct: A

    The pH is within the normal range (7.35–7.45) but BOTH the CO₂ and the bicarbonate are abnormal, which signals full compensation. To find the primary problem, split the normal range at 7.40: a pH of 7.37 sits on the acidic side, and the high CO₂ is the acidic driver — so this is a fully compensated respiratory acidosis (classic chronic CO₂ retainer whose kidneys have caught up).

    • A. Correct. Normal pH on the acidic side of 7.40 + high CO₂ = compensated respiratory acidosis.
    • B. Uncompensated would show a normal bicarbonate and an abnormal pH — here both are abnormal and pH is normal.
    • C. A mixed disorder would push the pH further off, not return it to normal.
    • D. The primary problem is acidic (pH 7.37 < 7.40) with CO₂ the driver, so respiratory, not metabolic alkalosis.
  6. 6

    An anxious client is hyperventilating in the emergency department. Which ABG pattern should the nurse expect if no compensation has occurred yet?

    Correct: D

    Hyperventilation blows off CO₂. Losing that acid raises the pH (alkalosis) and lowers the PaCO₂ — a respiratory alkalosis. With no compensation yet, the kidneys have not had time to dump bicarbonate, so HCO₃⁻ stays normal.

    • A. That pattern (low pH, high CO₂) is respiratory acidosis — the opposite problem.
    • B. A high bicarbonate would indicate metabolic alkalosis, not acute hyperventilation.
    • C. Low bicarbonate with low CO₂ suggests a compensated metabolic acidosis, not hyperventilation.
    • D. Correct. Blowing off CO₂ → high pH + low CO₂; normal bicarbonate = uncompensated.
  7. 7

    A client's ABG shows a high-anion-gap metabolic acidosis. Which finding in the client's history best explains this result?

    Correct: D

    A high anion gap means unmeasured acid has been ADDED to the blood. Lactic acid from shock/sepsis is a classic cause (remember MUDPILES). Diarrhea causes a normal-gap acidosis from bicarbonate loss, while NG suction and loop diuretics cause a metabolic ALKALOSIS, not acidosis.

    • A. Diarrhea loses bicarbonate → NORMAL-gap (hyperchloremic) acidosis, not high gap.
    • B. NG suction removes acid → metabolic alkalosis.
    • C. Loop diuretics cause a contraction metabolic alkalosis.
    • D. Correct. Added lactic acid widens the anion gap.
  8. 8

    What is the normal reference range for arterial pH?

    Correct: D

    Normal arterial pH is 7.35 to 7.45. Below 7.35 is acidemia; above 7.45 is alkalemia. Committing this range to memory is the first step of every ABG interpretation.

    • A. 7.25–7.35 is entirely within the acidemic range.
    • B. 7.00–7.35 spans severe acidemia up to the low-normal border.
    • C. 7.45–7.55 is entirely within the alkalemic range.
    • D. Correct. 7.35–7.45 is the normal arterial pH range.
  9. 9

    A client with an opioid overdose is difficult to arouse with a slow respiratory rate. Which acid-base disturbance is the priority concern?

    Correct: B

    Opioids depress the respiratory drive, causing hypoventilation. The client retains CO₂, which combines with water to form carbonic acid and drops the pH — a respiratory acidosis. The priority is supporting ventilation and oxygenation (and reversing the opioid); the retained CO₂ is what the ABG will show.

    • A. Metabolic alkalosis is unrelated to opioid-induced respiratory depression.
    • B. Correct. Hypoventilation retains CO₂ → respiratory acidosis.
    • C. Metabolic acidosis is a kidney/metabolism problem, not the primary issue in acute hypoventilation.
    • D. Respiratory alkalosis comes from hyperventilation, the opposite of opioid effect.
  10. 10

    A client has: pH 7.31, PaCO₂ 34 mmHg, HCO₃⁻ 16 mEq/L, Na⁺ 140, Cl⁻ 100. What is the anion gap, and what does it indicate?

    Correct: B

    Anion gap = Na⁺ − (Cl⁻ + HCO₃⁻) = 140 − (100 + 16) = 24 mEq/L. Normal is about 8–12, so 24 is elevated — a high-anion-gap metabolic acidosis, meaning unmeasured acid (lactate, ketones, toxins) has been added. The low pH and low bicarbonate confirm the metabolic acidosis; the gap tells you the cause category.

    • A. The anion gap does not diagnose respiratory disorders, and 40 is not the computed value.
    • B. Correct. 140 − (100 + 16) = 24, well above the normal 8–12.
    • C. 16 is not the computed gap, and that value would still be borderline-high, not normal.
    • D. 8 would be a miscalculation; recheck 140 − 116.